[geeks] hrm, possible?

[geeks at sunhelp.org]

On Fri, Jun 29, 2001 at 11:50:02AM -0500, Bill Bradford wrote:
> bash-2.02# ps -fe |grep ovw |grep display
>  mbarnes 20452     1  0 11:05:34 ?        0:09 /opt/OV/bin/ovw -rw -display 172.17.8.151:0
> dtrujill 20078     1  0 09:33:27 ?        0:17 /opt/OV/bin/ovw -ro -display 172.17.11.241:0
> lwilliam 20473     1  0 11:10:53 ?        0:10 /opt/OV/bin/ovw -ro -display 172.17.9.166:0
> ojanuari 20432     1  0 11:00:44 ?        0:10 /opt/OV/bin/ovw -ro -display 172.17.11.135:0
>  dher405 20049     1  0 09:29:07 ?        0:11 /opt/OV/bin/ovw/ -ro -display 172.17.11.136:0
>   jwells 20139     1  0 09:47:17 ?        0:19 /opt/OV/bin/ovw -ro -display 172.17.8.206:0
>  mbarnes 20029     1 45 09:28:10 ?       11:31 /opt/OV/bin/ovw -rw -display 172.17.8.151:0
>  kfuk855 20368     1  0 10:45:05 ?        0:08 /opt/OV/bin/ovw -rw -display 172.17.10.135:0
>   proman 20509     1  1 11:31:38 ?        0:09 /opt/OV/bin/ovw -ro -display 172.17.11.64:0
> 
> Anybody know if it would be possible to write a script (in whatever
> language necessary) that would detect the duplicate sessions (note
> processes 20432 and 20368, pointing to the same IP address)?  I'm
> working on some way to detect when one of our lusers forgets to 
> kill his session before the next shift starts....

#!/usr/bin/sh

POO=`ps -fe | grep ovw | grep display | awk '{print $NF}' | uniq -d`

if [ -z "$POO" ]
then
 echo "Nothing to worry about Bill. I dunno, get some coffee?"
else
 for i in `echo $POO`
 do
  echo "AAAAARRRRGH. Potential ovw duplicate session at $POO."  
 done
 echo "Note to Bill: Destroy Luser(s)."
fi

Brian.
-- 
Brian Scanlan, Systems Administrator.
Irish Times New Media - http://www.ireland.com