[SunHELP] Re: Swap Space shown Not As Defined

[Robert Novak]

On Fri, 18 Jan 2002, Dale Ghent displayed bad math in writing::

> On Fri, 18 Jan 2002 ymui at royalsunalliance.ca wrote:
> 
> | The system has 4 GB memory and 36 GB hard disk.
> | But 'format' does give the correct information though !
> 
> To see the actual size of your swap devices, use the command 'swap -l' and
> look at the 'blocks' column. The number you see is in 512KB blocks, so
> double that number and you will get you swap partition size in MB.

Actually if you double that number, you'll see the number of 256KB blocks.
To find out the number of megabytes, you cut it in half. 

For example, from a Solaris 8 machine here (Ultra 1):

	%  swap -l
	swapfile             dev  swaplo blocks   free
	/dev/dsk/c0t0d0s3   32,3      16 1572848 1572848
	/dev/dsk/c0t1d0s0   32,8      16 263856 263856
	/dev/dsk/c0t1d0s1   32,9      16 263856 263856

Here I have a pair of 128MB slices on the second disk, and a 768MB swap
slice on the first disk. It comes to a total of 1GB of swap space on disk.

	%  /usr/platform/sun4u/sbin/prtdiag |grep -i mem
	Memory size: 512 Megabytes
	%  df -k /tmp
	Filesystem            kbytes    used   avail capacity  Mounted on
	swap                 1349232      16 1349216     1%    /tmp

This shows that I have a total of 1.5GB of virtual memory, less whatever
I'm using. The "kbytes" column shows what's left of virtual memory
*before* /tmp usage is taken out, and "avail" shows what's left in /tmp. 
In this case, I'm using about 218MB ((1572864-1349232)/1024). 

	%  top |grep Memory
	Memory: 512M real, 359M free, 75M swap in use, 1320M swap free

Top shows a similar result... (512-359)+75 = 153+75 = 228MB.

Hope this helps.

--Rob

Robert Novak, Indyramp Consulting * rnovak at indyramp.com * indyramp.com/~rnovak
        "And it's been a long December and there's reason to believe
           Maybe this year will be better than the last...." -- counting crows